(x + 1) (x – 6) = x 2 – 6 x + x – 6 = x 2 – 5x – 6Įquate each factor to zero and solve to get (x + 1) (x – 6) = 0ĬASE 4: When b is negative and c is positive Now identify factors whose product is -6 and sum is –5:Ĭheck the factors using the distributive property. Therefore, x = 1, x = -5 are the solutions. Verify the factors using the distributive property. Identify the factors whose product is – 5 and sum is 4. Identify two factors with the product of 25 and sum of 10.ĬASE 2: When b is positive and c is negative Therefore, the solution is x = – 2, x = – 5 The factors of the quadratic equation are:(x + 2) (x + 5) Verify the factors using the distributive property of multiplication. Identify two factors with a product of 10 and a sum of 7: Solve the quadratic equation: x 2 + 7x + 10 = 0 You need to identify two numbers whose product and sum are c and b, respectively. To factorize a quadratic equation of the form x 2 + bx + c, the leading coefficient is 1. Factoring when the Coefficient of x 2 is 1 Therefore, we will use the trial and error method to get the right factors for the given quadratic equation. In this article, our emphasis will be based on how to factor quadratic equations, in which the coefficient of x 2 is either 1 or greater than 1. The are many methods of factorizing quadratic equations. Solve the following quadratic equation (2x – 3) 2 = 25Įxpand the equation (2x – 3) 2 = 25 to get
0 Comments
Leave a Reply. |
Details
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |